Question

Question #99b0f

Answer 1

`theta=pi/6+2n,5pi/6+2n` where `n` is a whole number.

Explanation:

First, set the two `r`s equal to each other:

`0=1-2sintheta`

Now solve for `theta`:

`-1=-2sintheta`

`1/2=sintheta`

`theta=sin^-1(1/2)`

`theta=pi/6+2n,5pi/6+2n` where `n` is a whole number.