A model train with a mass of #1 kg# is moving along a track at #24 (cm)/s#. If the curvature of the track changes from a radius of #96 cm# to #360 cm#, by how much must the centripetal force applied by the tracks change?

Question

1146 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-18T05:59:54

The change in centripetal force is #=0.044N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=1kg#

speed, #v=0.24ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=1*0.24^2/0.96=0.06N#

#F_2=mv^2/r_2=1*0.24^2/3.60=0.016N#

#DeltaF=0.06-0.016=0.044N#