A ball with a mass of 360 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 24 (kg)/s^2 and was compressed by 5/3 m when the ball was released. How high will the ball go?

1 Answer
May 19, 2017

9.448m

Explanation:

The mass has to be put in kg:
360g=0.36kg

We will use the conservation of energy.

The energy put by the spring:
U_("spring")=1/2kx^2
The energy for the gravitation:
U_g=mgy

If we apply the conservation of energy to this situation:
U_("spring")=U_g

We put the three equations together:
1/2kx^2=mgy

We isolate the height (y):
=>(kx^2)/(2mg)=y

We take all the values of our situation and put them in there:
=>y=((24)(5/3)^2)/((2)(0.36)(9.8)
=9.448m