Is #+-5i# the square root of #-25# ?

1 Answer
May 19, 2017

Yes and no.

Explanation:

The notation:

#+-5i#

is shorthand for the two values:

#5i" "# and #" "-5i#

So we can say that the polynomial:

#x^2+25 = 0#

has roots:

#x = +-5i#

meaning that it has roots:

#x = 5i" "# and #" "x = -5i#

In other words, #-25# has two square roots, namely #5i# and #-5i#.

By common definition and convention, the symbols #sqrt(-25)# denote #5i# (which is called the "principal square root"). So #-sqrt(-25) = -5i#. Both #sqrt(-25) = 5i# and #-sqrt(-25) = -5i# are square roots of #-25#.

#color(white)()#
Remarks

The #+-# symbol is very useful for shortening expressions that describe multiple values, but can be unclear when overused.

For example, we might write:

#(a+-b)^2 = a^2+-2ab+b^2#

which is true, provided that the chosen signs match.

Then again, we might say that the roots of:

#x^4-10x^2+1 = 0#

are:

#x = +-sqrt(2)+-sqrt(3)#

but in that case we would intend all #4# possible combinations.