Question #7d503

1 Answer
Narad T.
May 19, 2017

See proof below

Explanation:

We need

#tanx=sinx/cosx#

#sinx=2sin(x/2)cos(x/2)#

#cosx=2cos^2(x/2)-1#

Therefore,

#LHS=sinx/(1+cosx)#

#=(2sin(x/2)cos(x/2))/(1+2cos^2(x/2)-1)#

#=(2sin(x/2)cos(x/2))/(2cos^2(x/2))#

#=sin(x/2)/cos(x/2)#

#=tan(x/2)#

#=RHS#

#QED#

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