Question #f8198

1 Answer
May 19, 2017

See Below

Explanation:

Phythagorean Identity:
sin^2(theta)+cos^2(theta)=1
[sin^2(theta)+cos^2(theta)=1]/sin^2(theta)
cot^2(theta)+1=csc^2(theta)

Use it to solve the identity:

1+csc^2(theta)cos^2(theta)
1+cos^2(theta)/sin^2(theta)
1+cot^2(theta)
csc^2(theta)=RHS

QED