Question

What transformation can you apply to `y=sqrtx` to obtain the graph `y=-sqrt(1/6(x-11)`?

Answer 1

See below.

Explanation:

The second graph is basically just a modification of `y = sqrt(x)`.

First, `sqrt(x-11)` is multiplied by a coefficient of `-sqrt(1/6)`. Essentially, this means that the y-value of the second equation is `-(1/6)` times the y-value of `y=sqrt(x)`.

Finally, because 11 is subtracted from `x` within the square root, the graph shifts 11 units to the right.

I have attached the graphs of both equations for reference.