A ball with a mass of #144 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #48 (kg)/s^2# and was compressed by #6/4 m# when the ball was released. How high will the ball go?

Question

1207 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-20T06:07:07

The height is #=38.27m#

enter image source here

The spring constant is #k=48kgs^-2#

The compression is #x=6/4m#

The potential energy in the spring is

#PE=1/2*48*(6/4)^2=54J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

#PE_(ball)=54=0.144*9.8*h#

#h=54*1/(0.144*9.8)#

#=38.27m#