How do you evaluate #(5wx)/z# if w=6, x=0.4, y=1/2, z=-3?

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Answer 1 · 2017-05-20T13:44:50

See a solution process below:

To evaluate this expression substitute:

#color(red)(6)# for #color(red)(w)#

#color(blue)(0.4)# for #color(blue)(x)#

#color(green)(-3)# for #color(green)(z)#

#y# is extraneous and not needed for this problem.

Substituting and calculating gives:

#(5color(red)(w)color(blue)(x))/color(green)(z)# becomes:

#(5 xx color(red)(6) xx color(blue)(0.4))/color(green)(-3) => (30 xx color(blue)(0.4))/color(green)(-3) => 12/color(green)(-3) => -4#