How do you solve 3(6x)23>2(1+x)5?

1 Answer
May 21, 2017

x<5619

Explanation:

First, to make life simple, we make sure all three terms have the same denominator. The least common denominator of this equation, as the current denominators are 1, 2, and 5.

3(6x)2: We multiply this by 55
3(6x)255 = 5(183x)2555 = 9015x10

3: We multiply this by 1010
311010=3010

2(1+x)5: We multiply this by 22
2(1+x)522=4(1+x)52=4+4x10

Now, we combine and simplify. The denominators all cancel out through cross multiplication, so we are left with a simple inequality to solve:

9015x103010>4+4x10

=> (9015x)30>4+4x
=> 6015x>4+4x
=> 19x>56
=> x<5619