Question

What is the moment of inertia of a pendulum with a mass of `6 kg` that is `9 m` from the pivot?

Answer 1

The moment of inertia is `=486kgm^2`

Explanation:

The moment of inertia is

`I=mr^2`

The mass is `m=6kg`

The distance from the pivot is `r=9m`

The moment of inertia is

`I=mr^2=6*(9)^2=486kgm^2`