Question #24dc0
1 Answer
May 22, 2017
Explanation:
#"using the definition of " ""^nC""_r#
#• ""^nC""_r=(n!)/(r!(n-r)!)#
#"where " n! =n(n-1)(n-2)(n-3)..... xx1#
#rArr""^(10)C""_4=(10!)/(4!xx6!)larr" 6! cancel"#
#color(white)(xxxxxx)=(10xx9xx8xx7)/(4xx3xx2xx1)#
#color(white)(xxxxxx)=210#