How do you find the slope of #(2, -1), (-8, -2) #?

2 Answers
May 22, 2017

The slope of the line passing through #(2,-1) and (-8,-2)# is #1/10#

Explanation:

The slope of the line passing through #(2,-1) and (-8,-2)# is

#m= (y_2-y_1)/(x_2-x_1)= (-2+1)/(-8-2)=(-1)/-10=1/10# {Ans]

May 22, 2017

#"slope "=1/10#

Explanation:

#"to calculate the slope use the "color(blue)"gradient formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1),(x_2,y_2)" 2 coordinate points"#

#"the points are " (x_1,y_1)=(2,-1),(x_2y_2)=(-8,-2)#

#rArrm=(-2-(-1))/(-8-2)=(-1)/(-10)=1/10#