Question #429a0

1 Answer
A08
May 23, 2017

#26.bar6" kmh"^-1#

Explanation:

Let one way distance driven by Abdul is #=s" km"#
Time taken to drive to school#=s/20" h"#
Time taken for the return trip#=s/40" h"#
Total time for the return trip#=s/20+s/40=(3s)/40" h"#

Total distance driven#=s+s=2s" km"#

Average speed for Abdul's trip#="Total distance of return trip"/"Total time taken for the return trip"#
#=(2s)/((3s)/40)#
#=(2sxx40)/(3s)#
#=26.bar6" kmh"^-1#

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