A ball with a mass of #650 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #32 (kg)/s^2# and was compressed by #7/8 m# when the ball was released. How high will the ball go?

Question

1223 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-23T13:05:18

The height is #=1.92m#

enter image source here

The spring constant is #k=32kgs^-2#

The compression is #x=7/8m#

The potential energy in the spring is

#PE=1/2*32*(7/8)^2=12.25J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

#PE_(ball)=12.25=0.65*9.8*h#

#h=12.25*1/(0.65*9.8)#

#=1.92m#