How do you simplify #(- 2x y ^ { 2} z ) ^ { 2} ( 2x ^ { 4} z ^ { 2} ) ^ { 3}#?

1 Answer
Mia
May 23, 2017

#=32x^14z^8y^4#

Explanation:

#(-2xy^2z)^2(2x^4z^2)^3#
#" "#
#=((-2)^2(x)^2(y^2)^2(z^2))(2^3(x^4)^3(z^2)^3)#
#" "#
#=(4x^2y^4z^2)(8x^12z^6)#
#" "#
#=(4xx8)(x^2xxx^12)(z^2xxz^6)y^4#
#" "#
#=32x^(2+12)z^(2+6)y^4#
#" "#
#=32x^14z^8y^4#

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