How do you simplify #(\frac { 12a ^ { - 3} } { 4\sqrt { a } } )#?

1 Answer
John C.
May 24, 2017

refer below

Explanation:

#(12a^-3)/(4sqrta) = (12a^-3)/(4a^(1/2)#

#=(cancel(12)a^-3)/(cancel(4)a^(1/2)#

#=(3a^-3)/a^(1/2)#

The division of "a" can be done as such: #a^-3/a^(1/2) = a^(-3-1/2)#

(Alternatively, if we have #a^-3*a^(1/2) = a^(-3+1/2)#)

This can be done when the exponents have the same base ie "a".

#=3a^(-3-1/2)#

#=3a^-(7/2)#

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