How do you find the slope of the line that passes through the points (-1,0), (3,-2)?

2 Answers
May 24, 2017

The Slope of the line is #-1/2#.

Explanation:

The slope of the line, #m#, is found by

#m = (y_2-y_1)/(x_2-x_1)#

So

#m= (-2-0)/(3-(-1))#

#= -2/4 #

#= -1/2#

May 24, 2017

#"slope "=-1/2#

Explanation:

#"to calculate the slope use the "color(blue)"gradient formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1),(x_2,y_2)" 2 points on the line"#

#"the points are " (x_1,y_1)=(-1,0),(x_2,y_2)=(3,-2)#

#rArrm=(-2-0)/(3-(-1))=(-2)/4=-1/2#