If an electron in a hydrogen atom makes a transition from the #n=2# level to the #n=4# level, calculate the energy in Joules of this photon?

1 Answer
Doc048 · Ernest Z.
May 25, 2017

#E = 4.09 xx 10^-19"J"#

Explanation:

#DeltaE_(n=2->4) = -A_H(1/n_f^2 -1/n_i^2)#

#n_(f)# = final energy level = 4
#n_(i)# = initial energy level = 2
#A_H = 2.18 xx 10^-18"J"#

#DeltaE_(n=2->4) = -2.18 xx10^-18"J"(1/4^2 -1/2^2)#
# = 4.09 xx 10^-19"J"#

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