How do you solve #9/(3x)=4/(x+2)#?

2 Answers
EZ as pi
May 25, 2017

#x=6#

Explanation:

We have AN EQUATION, with ONE term (a fraction) on EACH side.

Therefore we can cross-multiply:

#9/(3x) = 4/(x+2)#

#3x xx 4 = 9 xx(x+2)#

#12x = 9x+18" "larr# subtract #9x# from both sides

#12x-9x=18#

#3x = 18#

#x=6#

EZ as pi
May 25, 2017

#x=6#

Explanation:

We have AN EQUATION, with ONE term (a fraction) on EACH side.

Therefore we can cross-multiply:

#9/(3x) = 4/(x+2)#

#3x xx 4 = 9 xx(x+2)#

#12x = 9x+18" "larr# subtract #9x# from both sides

#12x-9x=18#

#3x = 18#

#x=6#

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