If #8 L# of a gas at room temperature exerts a pressure of #15 kPa# on its container, what pressure will the gas exert if the container's volume changes to #15 L#?

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Answer 1 · 2017-05-26T12:08:34

The pressure is #=8kPa#

We apply Boyle's Law

#P_1V_1=P_2V_2#

The initial volume is #V_1=8L#

The initial pressure is #P_1=15kPa#

The final volume is #V_2=15L#

The final pressure

#P_2=V_1/V_2*P_1#

#=8/15*15#

#=8kPa#