Question #e2ec5

2 Answers
May 27, 2017

.

Explanation:

P = force/area =(kgms^-2)/m^2= kgm^-1s^-2
v= ms^-1
A=m^2

Q= (kgm^-1s^-2)/(ms^-1 m^2)

Q=kgm^(-1-3)s^(-2-(-1)

Q=kgm^-4s^-1

May 27, 2017

Kgm^-4sec^-1

Explanation:

See , ATQ

Q=(P)/(v*A)
=>(F/A)/(m/s*A)
=>(F)/(v*A^2)
=>(MLT^(-2))/(LT^(-1)*L^5)

=>(MLT^-2)/(L^5T^-1)=ML^-4T^-1

hence , equals to Kgm^-4sec^-1