How do you simplify #6sqrt54#?

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Answer 1 · 2017-05-27T15:15:34

#=18sqrt6#

the first step when working with roots is to find the factors of the radicand. (#54#), using squares if possible.

#6sqrt54 = 6 sqrt(9xx6)" "larr# find the roots if possible.

#6 sqrt(9xx6)" "larr (sqrt9 =3)#

#=6 xx 3sqrt6#

#=18sqrt6#

Answer 2 · 2017-05-27T15:28:22

#color(brown)(18sqrt6#

#6sqrt54#

#:.=6sqrt(3*3*3*2)#

#:.sqrt3 xx sqrt3=3#

#:.=6sqrt(underline(3*3)*3*2)#

#:.=6 xx 3sqrt6#

#:.color(brown)(=18sqrt6#