Question

How do you combine `\frac { 3} { 2b ( 3b - 2) } - \frac { 3} { 2b }` into one term?

Answer 1

`(9-9b)/(6b^2-4b)`

Explanation:

`3/(2b(3b-2)) - 3/(2b)`
`= (3/(2b))(1/(3b-2)-1)`
`= (3/(2b))((1-3b+2)/(3b-2))`
`= (3/(2b))((3-3b)/(3b-2))`
`= (9-9b)/(6b^2-4b)`