Question

What is the Cartesian form of `( -3, (-19pi)/8 )`?

Answer 1

`(-3cos((-19pi)/8), -3sin((-19pi)/8))`
or
`approx(-1.15,2.77)`

Explanation:

Polar coordinates take the form `(r,theta)`

Conversion of polar coordinates to rectangular as follows:
`x=rcostheta`
`y=rsintheta`

Therefore, `x=-3cos((-19pi)/8), y=-3sin((-19pi)/8)`