Question

How do you find the x and y intercept of `y-3/5x-12`?

Answer 1

Assumption: The expression should be an equation and of the form
`y=3/5x-12`

y-intercept`->(x,y)=(0,-12)`
x-intercept`->(x,y)=(20,0)`

Explanation:

y-intercept is the same as the constant `->y=-12`

That is because the y-intercept is at `x=0`
`y=3/5(0)-12" "=" "12`

y-intercept`->(x,y)=(0,-12)`

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x-intercept is at `y=0`

`=>y=0=3/5x-12`

Add 12 to both sides

`12=3/5x`

Multiply both sides by 5/3

`5/3xx 12=3/5xx5/3xx x`

`5xx12/3=1xx1xx x`

`20=x`

x-intercept`->(x,y)=(20,0)`