How do you solve #\ln ( 3p - 4) = \ln ( - 3p - 10)#?

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Answer 1 · 2017-05-29T12:49:42

We get the value #p=-1#

The #ln# disappear leaving this equation:

#cancel(ln)(3p-4) = cancel(ln)(-3p-10)#

#3p-4=-3p-10#

Rearrange to have all unknowns on one side and numbers on the other:

#3p+3p=-10+4#

#6p= -6#

#p= -1#