How do you find the antiderivative of #f(x)=(2x+3)(3x-7)#?

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Answer 1 · 2017-05-30T21:15:12

#F(x)=2x^3-5x^2/2-21x+# constant

Factor out the expression.

#(2x+3)(3x-7)=6x^2-14x+9x-21#

#=6x^2-5x-21#

The antiderivative of #ax^n# is

#(ax^(n+1))/(n+1)#

The antiderivative is as follows

#F(x)=2x^3-5x^2/2-21x+# constant