What is the moment of inertia of a pendulum with a mass of #9 kg# that is #11 m# from the pivot?

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Answer 1 · 2017-05-31T06:38:33

The moment of inertia is #=1089kgm^2#

We assume that it is a point mass.

The moment of inertia is

#I=mr^2#

The mass is #m=9kg#

The distance is #r=11m#

The moment of inertia is

#I=mr^2=9*11^2=1089kgm^2#