How do you evaluate #(c^2-5b)/b# when #b=4# and #c=8#?

1 Answer
May 31, 2017

See a solution process below:

Explanation:

To evaluate this expression substitute #color(red)(4)# for each occurrence of #color(red)(b)# and substitute #color(blue)(8)# for each occurrence of #color(blue)(c)#. Then calculate the result:

#(color(blue)(c)^2 - 5color(red)(b))/color(red)(b)# becomes:

#(color(blue)(8)^2 - (5 xx color(red)(4)))/color(red)(4) => (64 - 20)/color(red)(4) => 44/4 =>#

#11#