How do you solve #x= \frac { 2x ^ { 2} - 3} { 5}#?

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Answer 1 · 2017-05-31T21:32:44

#x=-1/2# and #x=3#

Multiply both sides by #5#

#5x=2x^2-3#

Subtract #2x^2# from both sides

#-2x^2+5x=-3#

Add three to both sides

#-2x^2+5x+3=0#

Factor out this quadratic
#(2x+1)(x-3)=0#

Set each term to #0# and solve

#{:(2x+1=0color(white)(aa),x-3=0),(2x=-1color(white)(aa),x=3),(x=-1/2color(white)(aa),color(white)(aaa)):}#