Question

Question #921b9

Answer 1

`Pb(NO_3)_2 + Cl^(-) = PbCl_2 + NO_3^-`

Explanation:

Cl doesn't exist as single atom, it can exist as `Cl^-` that is an anion quite stable. It can react with the cations: `Ag^+, Hg_2^(2+)` and partially with `Pb^(2+)` cold, to form insoluble compounds, while the salts of nitrate ion are all soluble
So you can have:
`Pb(NO_3)_2 + Cl^(-) = PbCl_2 + NO_3^-`
the molecule `Cl_2` instead, is a discrete oxidant, but doesn't react neither with `Pb^(2+)` nor with nitrate ion