How do you simplify #(-2f^3g^2h^0)/(8f^2g^2)#?

2 Answers
Jun 1, 2017

ans- -1fh^0/4

Explanation:

-2 (f^3) (g^2) (h^0)/ 8f^2g^2 ----------------(on solving and cancelling in both numerator and denominator f^2, g^2 are common and hence get cancelled)
= -1f(h^0)/4 (thus answer)
...............................hope it helps.....................:)

Jun 1, 2017

#(-f)/4#

Explanation:

#(-2f^3g^2h^0)/(8f^2g^2)#

#(-2)/8xxf^(3-2)g^(2-2)xxh^0#

#(-1)/4xxfxxg^0xxh^0#

#(-f)/4#