Question

Question #3d50c

Answer 1

+1

Explanation:

to calculate the oxidation no. of s let it be x
wkt oxd no of H= +1
oxd no of O= -2
no ion charge so total charge =0
then 2(+1) + 2x + 2*(-2) =0
=> +2 + 2x + (-4) =0
=> 2x -2 =0
=> 2x= 2
=> x=1 ( oxd no of s)
............................hope it helps........................:)