How do you find the instantaneous rate of change of the function #f(x)= 3/(x-5)# when x=1?

Question

7114 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-01T06:27:40

The instantaneous rate of change is #=-3/16#

enter image source here

We need

#(1/x)'=-1/x^2#

Here, we have

#f(x)=3/(x-5)#

#f'(x)=-3*1/(x-5)^2#

#f'(1)=-3/(1-5)^2=-3/16#