How do you solve x^ { 2} - 8x - 78= 8?

1 Answer
Jun 2, 2017

a little simplification needs to be done
ie, x^2 - 8x-78=8
x^2-8x-86=0 ( bringing +8 to left side)

Explanation:

x= -b +- sqrt(b^2-4ac)/2/a
solve for x putting the values of a =+1 , b= -8 , c= - 86
and find the answer , it will give the most appropriate answer
........................hope it helps.......................:)