How do you simplify #\frac { 8c d ^ { 4} } { 2c d ^ { 8} \cdot c d \cdot c ^ { 6} d }#?

Question

1434 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-02T07:25:54

#(8cd^4)/(2cd^8*cd*c^6d)=4/(c^7d^6)#

#(8cd^4)/(2cd^8*cd*c^6d)#

= #(8cd^4)/(2cxxcxxc^6xxd^8xxd xxd)#

= #(8cd^4)/(2c^((1+1+6))xxd^((8+1+1))#

= #(8cd^4)/(2c^8xxd^10)#

= #8/2xxc/c^8xxd^4/d^10#

= #4xx1/c^((8-1))xx1/d^((10-4))#

= #4xx1/c^7xx1/d^6#

= #4/(c^7d^6)#