How do you find the domain of #f(x) = (2x)/(2x-5)#?

1 Answer
Jun 3, 2017

The domain of #f(x)# is #(-oo, 5/2)uu(5/2, +oo)#

Explanation:

#f(x) = (2x)/(2x-5)#

#f(x)# is defined for all x except where #2x-5=0#
#:.f(x)# is defined #forall x in RR: x!=5/2#

Thus the domain of #f(x)# is #(-oo, 5/2)uu(5/2, +oo)#

We can see this from the graph of #f(x)# below.

graph{2x/(2x-5) [-7.89, 14.61, -4.575, 6.665]}