How do you solve $5x^2+5=-13x$ using the quadratic formula?

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Answer 1 · 2017-06-03T08:38:25

$x=-13/10+sqrt(69), or -13/10-sqrt(69)$

Firstly, in any quadratic equation, you want to get it in the form $ax^2+bx+c$ .

To do that, add $13x$ to both sides.

$5x^2+13x+5=0$

Now, we can get the following ; $a=5, b=13, c=5$

The quadratic formula is this : $(-b+-sqrt(b^2-4ac))/(2a)$

Substitute the values

$(-13+-sqrt(13^2-(4)(5)(5)))/((2)(5))$

$(-13+sqrt(69))/10$

$-13/10+sqrt(69), -13/10-sqrt(69)$

How do you solve 5x^2+5=-13x5x^2+5=-13x using the quadratic formula?