How do you simplify #-4sqrt15*-sqrt3#?

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Answer 1 · 2017-06-03T10:46:01

#12sqrt5#

Given, #-4sqrt15* -sqrt3 = (-xx-)4sqrt(3*5)*sqrt3#

#rArr +4sqrt3*4sqrt5*sqrt3#

#rArr 4sqrt3sqrt3*sqrt5#

#rArr 4*3^(1/2)3^(1/2)*sqrt5#

#rArr 4*3^(1/2+1/2)*sqrt5#

#rArr 4*3^(2/2)*sqrt5#

#rArr 4*3*sqrt5 = 12sqrt5#