How do you solve #(r+3)/(r-4) = (r-5)/(r+4)#?
2 Answers
Explanation:
Eliminate the fractions by cross multiplying:
Distribute each binomial to get two quadratic equations:
Subtract
Add 9 to both sides:
Subtract 12 from both sides:
Divide both sides by 16:
Simplify:
To check your answer, plug in
From there, just simplify:
Explanation:
First cross multiply to give you a linear equation.
Then make the equation equal zero.
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