How do you find the slope of the graph #f(x)=3(5-x)^2# at (5,0)?
1 Answer
Jun 4, 2017
Explanation:
#color(orange)"Reminder"#
#f'(x)=m" at " x=a#
#f(x)=3(25-10x+x^2)=75-30x+3x^2#
#rArrf'(x)=-30+6x#
#rArrf'(5)=-30+30=0#