What is the average translational kinetic energy of molecules in an ideal gas at 37°C?
1 Answer
Jun 6, 2017
The average translational energy of a molecule is given by the equipartition theorem as,
#E = (3kT)/2# where#k# is the Boltzmann constant and#T# is the absolute temperature.
For
Thus,
#implies E = 641.7 * 10^(-23) J#
Or