How do you solve the system 3x + y = 5 and -2x + 3y =4?

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Answer 1 · 2017-06-06T08:49:31

#x = 1 #
#y = 2#

First you would multiply each equation by the coefficient of x

#-2(3x+y = 5)#
#3(-2x + 3y = 4)#

Which is simplified to

#-6x - 2y = -10#
#-6x + 9y = 12#

Then you would minus both equations together cancelling #x# to get the value of #y#

#-11y = -22#

#y= 22/11#

#y = 2#

Put 2 in replace of #y# into one of the original equation to find x

#3x + 2 = 5#

#3x = 5 - 2#

#x = (5 - 2)/3#

#x = 1#