Question

How do you divide `\frac { 13u ^ { 4} + 6u ^ { 3} + 4u ^ { 2} } { 2u ^ { 2} }`?

Answer 1

`\frac{13}{2}u^2 + 3u + 2`

Explanation:

The denominator is only a single term so you can split the fractions up and divide them individually: `\frac{13u^4 + 6u^3 + 4u^2}{2u^2} = \frac{13u^4}{2u^2} + \frac{6u^3}{2u^2} + \frac{4u^2}{2u^2}`, and the "`u`"s cancel out to give: `\frac{13}{2}u^2 + 3u + 2`. I hope I have explained it in enough detail.

Answer 2

`13/2u^2+3u+2`

Explanation:

`"'split' up the terms in the numerator dividing each one by"`
`"the denominator"`

`rArr(13u^4+6u^3+4u^2)/(2u^2)`

`=(13u^4)/(2u^2)+(6u^3)/(2u^2)+(4u^2)/(2u^2)`

`=13/2u^2+3u+2`