How do you evaluate #a(b^x)# given a=4, b=1, x=7?

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Answer 1 · 2017-06-06T23:38:05

4

Let's substitute #a=4, b=1, x=7#:

#a(b^x)#

#4(1^7)#

expand #1^7#

#4(1 xx 1 xx 1 xx 1 xx 1 xx 1 xx 1 )#

simplify

#4(1)#

#4 xx 1# gives us #4#