How do you factor #8v ^ { 2} + 23v - 3# by grouping?

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Answer 1 · 2017-06-07T02:42:34

Break the trinomial into two binomials (8v -1) (1v +3)

In the #Ax^2 + Bx + C#

The C value of -3 indicates that one of the binomials must be positive and one must be negative.

The B value of + 23 indicates that the positive value must be greater than the negative value.

The positive value - the negative value = +23.

Factor 8 and 3 to see possible combinations

8 can be factored into # 8 xx 1 : 4 xx 2 #
3 can only be factored into # 3 xx 1 #

# (8xx3) - ( 1 xx 1) = 23# so that is the combination that works.

# 8v^2 + 23v -3 = ( 8v -1) xx ( 1v +3) #