Question

How do you find all six trigonometric function of `theta` if the point (12, -5) is on the terminal side of `theta`?

Answer 1

t is in Quadrant 4.
`tan t = y/x = - 5/12`
`cos^2 t = 1/(1 + tan^2 t) = 1/(1 + 25/144) = 144/169`
`cos t = 12/13` (t is in Quadrant 4)
`sin t = tan t.cos t = (-5/12)(12/13) = - 5/13`
`cot t = 1/(tan) = - 12/5`
`sect = 1/(cos) = 13/12`
`csc t = 1/(sin) = -13/5`