Question #0bf56

1 Answer
Jun 7, 2017

See explanation below.

Explanation:

You need to get #Q_2# by itself.
First, write 280,000 in scientific notation:

#2.8*10^5=1.12*10^8*(1*10^-4*Q_2)/(0.01^2)#

Rewrite #0.0001# as #1*10^-4# then cancel out the like terms:

#2.8*10^5=1.12*10^8*(1*10^-4*Q_2)/(1*10^-4)#

#2.8*10^5=1.12*10^8*Q_2#

Divide both sides by #1.12*10^8#

#(2.8*10^5)/(1.12*10^8)=Q_2#

Break up the left hand side and apply this index law:

#(a*10^x)/(b*10^y)=(a/b)*10^(x-y)#

#Q_2=(2.8/1.12)*(10^5/10^8)=(2.5)*10^(5-8)#

#Q_2=2.5*10^-3#