How do you multiply (b + 14) ^ { 2}(b+14)2 ?

2 Answers
Jun 7, 2017

b^2 + 28 b + 196b2+28b+196

Explanation:

(b + 14)^2 = (b + 14)(b + 14)(b+14)2=(b+14)(b+14)

= (b * b) + (b * 14) + (14 * b) + (14 * 14)=(bb)+(b14)+(14b)+(1414)

= b^2 + 14 b + 14 b + 196=b2+14b+14b+196

= b^2 + 28 b + 196=b2+28b+196

Jun 7, 2017

b^2+28b+196b2+28b+196

Explanation:

"express " (b+14)^2=(b+14)(b+14)express (b+14)2=(b+14)(b+14)

"each term in the second bracket is multiplied by each "each term in the second bracket is multiplied by each
"term in the first bracket as shown below"term in the first bracket as shown below

(color(red)(b+14))(b+14)(b+14)(b+14)

=color(red)(b)(b+14)color(red)(+14)(b+14)=b(b+14)+14(b+14)

=(color(red)(b)xxb)+(color(red)(b)xx14))+(color(red)(14)xxb)+(color(red)(14)xx14)=(b×b)+(b×14))+(14×b)+(14×14)

=b^2+14b+14b+196=b2+14b+14b+196

=b^2+28b+196=b2+28b+196